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Answer 1 · 2016-03-23T12:46:11

#((9/16)^-3)/2=2^11/3^6#

#a^-n=1/(a^n)#

therefore:

#((9/16)^-3)/2=1/(9/16)^3times1/2=1/(9^3/16^3)times1/2=16^3/9^3times1/2=#

#=(2^4)^3/(3^2)^3times1/2=#

Using the properties

#(a^n)^m=a^(ntimesm)#

#a^n/a^m=a^(n-m)#

#=2^12/3^6times1/2=2^(12-1)/3^6=2^11/3^6#