How many moles of oxygen gas are required to combust a #4*mol# quantity of acetylene completely?
The balanced chemical equation is given. Each mole of acetylene requires two and a half moles of oxygen gas. So if 4 mol acetylene are combusted, some 10 moles of dioxygen are necessary.
First thing to do is to balance the chemical equation; The balanced equation is:
#2C_2H_2 + 5O_2 rarr 4CO_2 + 2H_2O#
Then use the coefficients, which represents the number of mol of its compound/molecules in said reaction, to get the number of mol of
- Multiply the mol of acetylene as provided in the problem (
#4 mol C_2H_2#) with the convertion ratio of the moles of acetylene and oxygen molecules ( #(5 mol O_2)/(2mol C_2H_2#)) based on the balanced equation;
- Make sure to cancel the mole of
#C_2H_2#and get your desired mole of #O_2#molecules.
- The answer per computation is 10 mol of