# Question #959f8

Mar 15, 2016

$m a s s = 2.18 g C a C {l}_{2} \cdot 6 {H}_{2} O$

#### Explanation:

Take the molar mass of $C a C {L}_{2} \cdot 6 {H}_{2} O$
$C a = 1$x$40 = 40$
$C l = 2$x$35 = 70$
${H}_{2} O = 6$x$18 = 108$
Total=$218$ grams per mole
2. All other data needed to solve the problem are given:
$V = 100 m l = 0.100 L i$
$M = 0.1 \frac{m o l}{L i}$
3. Plug in data using the formula:
$M = \frac{\textcolor{red}{n}}{L i s o l u t i o n}$
but:
$\textcolor{red}{n} = \frac{m a s s}{m o l a r m a s s}$
4. Therefore; plug in the value to derive new formula to find the mass of $C a C {l}_{2} \cdot 6 {H}_{2} O$
$M = \frac{\frac{m a s s}{m o l a r m a s s}}{L i s o l u t i o n}$
5. Rearrange the formula isolating $m a s s$
$m a s s = m o l a r m a s s$x$M$x$L i s o l u t i o n$
6. Plug in values and ensure to cancel out units to obtain $m a s s = 2.18 g C a C {l}_{2} \cdot 6 {H}_{2} O$