Question #959f8

1 Answer
Mar 15, 2016

Answer:

#mass=2.18 g CaCl_2*6H_2O#

Explanation:

Take the molar mass of #CaCL_2*6H_2O#
#Ca = 1 #x# 40=40#
#Cl=2 #x# 35=70#
#H_2O=6 #x# 18=108#
Total=#218# grams per mole
2. All other data needed to solve the problem are given:
#V=100 ml=0.100 Li#
#M=0.1 (mol)/(Li)#
3. Plug in data using the formula:
#M=color(red)n/(Li solution)#
but:
#color(red)n=(mass)/(molar mass)#
4. Therefore; plug in the value to derive new formula to find the mass of #CaCl_2*6H_2O#
#M=((mass)/(molar mass))/(Li solution)#
5. Rearrange the formula isolating #mass#
#mass=molar mass #x# M #x# Li solution#
6. Plug in values and ensure to cancel out units to obtain #mass=2.18 g CaCl_2*6H_2O#