# Question #fd348

Mar 18, 2016

$\frac{1 - \left(- \frac{1}{3}\right) = \frac{4}{3}}{2} = \frac{2}{3}$ and $\sqrt{\frac{2}{3}} = \frac{\sqrt{2}}{\sqrt{3}} = \frac{\sqrt{6}}{3}$

#### Explanation:

Take the $- \left(- \frac{1}{3}\right)$ and turn it into $\frac{1}{3}$

Then, turn the $1 \frac{1}{3}$ into $\frac{4}{3}$

When you divide $\frac{4}{3}$ by $2$ it gets you $\frac{2}{3}$

Next, using that one square root identity, $\sqrt{\frac{2}{3}}$ becomes $\frac{\sqrt{2}}{\sqrt{3}}$

Finally, remove the radical on bottom by multiplying by $\frac{\sqrt{3}}{\sqrt{3}}$ to turn $\frac{\sqrt{2}}{\sqrt{3}}$ into $\frac{\sqrt{6}}{3}$.