# Question #7c911

Mar 24, 2016

$m = \frac{Q}{\Delta T {C}_{p}}$

#### Explanation:

Using the thermochemistry heat quantity equation $Q = m \Delta T {C}_{p}$
we can solve for mass by isolating the $m$ where:

Q = Heat in Joules
m = mass in kilograms
$\Delta T$ = change in temperature $\left({t}_{f} - {t}_{i}\right)$
${C}_{p}$ = Specific Heat Capacity in $\frac{J}{{g}^{o} C}$

$Q = m \Delta T {C}_{p}$
Begin by isolating the $m$ variable

$\frac{Q}{\Delta T {C}_{p}} = m \frac{\cancel{\Delta T {C}_{p}}}{\cancel{\Delta T {C}_{p}}}$

$m = \frac{Q}{\Delta T {C}_{p}}$