# Question #3f817

Apr 4, 2016

$6$ times that of the Moon's

#### Explanation:

Acceleration due to gravity on any astronomical body is:

${g}_{b o \mathrm{dy}} = G {M}_{b o \mathrm{dy}} / {r}_{b o \mathrm{dy}}^{2}$

${g}_{E a r t h} = G {M}_{E a r t h} / {r}_{E a r t h}^{2}$

${g}_{M o o n} = G {M}_{M o o n} / {r}_{M o o n}^{2}$

You can Google/Bing/Yahoo for the masses and the radii of the Earth and the Moon and find the ratio ${g}_{E a r t h} / {g}_{M o o n}$. It should be around $6$.