# Question #85f29

##### 2 Answers

The answer is really easy. It just takes to use molarity definition to calculate it.

#### Explanation:

Molarity or molar concentration,

We just must find the number of moles of solute, so:

#### Explanation:

A solution's **molarity** tells you how many *moles of solute* you get **in one liter** of solution.

In essence, molarity is a measure of concentration that deals with moles of solute and liters of solution. This means that a solution's molarity can be used as a *conversion factor* that can help you convert moles to liters of solution and vice versa.

In your case, the solution is said to have a molarity of

#c = "0.325 M" = "0.325 mol L"^(-1)#

This tells you that **every liter** of this solution will contain **moles** of solute.

Use this as a conversion factor to see how many moles you'd get in

#1.85 color(red)(cancel(color(black)("L solution"))) * overbrace("0.325 moles"/(1color(red)(cancel(color(black)("L solution")))))^(color(purple)("a molarity of 0.325 M")) = "0.60125 moles"#

Rounded to three **sig figs**, the answer will be

#"no. of moles of solute" = color(green)(|bar(ul(color(white)(a/a)0.601color(white)(a/a)|)))#