# Question 85f29

Apr 6, 2016

The answer is really easy. It just takes to use molarity definition to calculate it.

#### Explanation:

Molarity or molar concentration, $M$ is defined by:

$M = \left\{\text{number of solute moles"}/{"number of litres of disolution}\right\}$

We just must find the number of moles of solute, so:

$\text{number of moles of solute} =$
$= 0.325 \text{ M" cdot 1.85 " L" = 0,60125 " mol}$

Apr 6, 2016

$\text{0.601 moles}$

#### Explanation:

A solution's molarity tells you how many moles of solute you get in one liter of solution.

In essence, molarity is a measure of concentration that deals with moles of solute and liters of solution. This means that a solution's molarity can be used as a conversion factor that can help you convert moles to liters of solution and vice versa.

In your case, the solution is said to have a molarity of

$c = {\text{0.325 M" = "0.325 mol L}}^{- 1}$

This tells you that every liter of this solution will contain "0.325 moles of solute.

Use this as a conversion factor to see how many moles you'd get in $\text{1.85 L}$ of solution

1.85 color(red)(cancel(color(black)("L solution"))) * overbrace("0.325 moles"/(1color(red)(cancel(color(black)("L solution")))))^(color(purple)("a molarity of 0.325 M")) = "0.60125 moles"#

Rounded to three sig figs, the answer will be

$\text{no. of moles of solute} = \textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} 0.601 \textcolor{w h i t e}{\frac{a}{a}} |}}}$