The answer is really easy. It just takes to use molarity definition to calculate it.
Molarity or molar concentration,
We just must find the number of moles of solute, so:
In essence, molarity is a measure of concentration that deals with moles of solute and liters of solution. This means that a solution's molarity can be used as a conversion factor that can help you convert moles to liters of solution and vice versa.
In your case, the solution is said to have a molarity of
#c = "0.325 M" = "0.325 mol L"^(-1)#
This tells you that every liter of this solution will contain
Use this as a conversion factor to see how many moles you'd get in
#1.85 color(red)(cancel(color(black)("L solution"))) * overbrace("0.325 moles"/(1color(red)(cancel(color(black)("L solution")))))^(color(purple)("a molarity of 0.325 M")) = "0.60125 moles"#
Rounded to three sig figs, the answer will be
#"no. of moles of solute" = color(green)(|bar(ul(color(white)(a/a)0.601color(white)(a/a)|)))#