Question #9a3ca

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Question #9a3ca

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Answer 1 · 2017-10-05T05:28:50

Very simple approach...
See the answer below...
Hope it helps...

Explanation:

We definitely know ${sin}^{2} x + {cos}^{2} x = 1$ $color(red)(sin^2x+cos^2x=1$

If we get $sin x = \frac{1}{2}$ $sinx=1/2$ then we can use the formula,
i.e,
${(\frac{1}{2})}^{2} + {cos}^{2} x = 1$ $(1/2)^2+cos^2x=1$
$\Rightarrow {cos}^{2} x = \frac{3}{4}$ $=>cos^2x=3/4$
$\Rightarrow cos x = \frac{\sqrt{3}}{2}$ $=>cosx=sqrt3/2$

Similarly,
${(\frac{1}{4})}^{2} + {cos}^{2} y = 1$ $(1/4)^2+cos^2y=1$
$\Rightarrow {cos}^{2} y = \frac{15}{16}$ $=>cos^2y=15/16$
$\Rightarrow cos y = \frac{\sqrt{15}}{4}$ $=>cosy=sqrt15/4$

Thank you...

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Question #9a3ca

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