# Question #9a3ca

##### 1 Answer

Oct 5, 2017

#### Answer:

Very simple approach...

See the answer below...

Hope it helps...

#### Explanation:

We definitely know

If we get

#sinx=1/2# then we can use the formula,

i.e,

#(1/2)^2+cos^2x=1#

#=>cos^2x=3/4#

#=>cosx=sqrt3/2# Similarly,

#(1/4)^2+cos^2y=1#

#=>cos^2y=15/16#

#=>cosy=sqrt15/4#

Thank you...