# Question #2879f

$1.91 k g {m}^{-} 3$
Density, $\rho$, is $\text{mass"/"volume}$, given in the units $\frac{k g}{m} ^ 3$ or $k g {m}^{-} 3$
$\rho = \frac{42}{22} \frac{k g}{m} ^ 3 = 1.91 k g {m}^{-} 3$