Solve for equilibrium ?
The situation given in the question has been shown in the figure.
#"weight of the shaft"=5.097Mgf=5097kgf#
# "O is the point of suspension, OP and OQ are chains of 4m "#
# "R is CG , OR is the vertical line along which total weight acts"#
PR =1.25m and RQ = 2.75m
#T_1 ="Tension along PQ" and T_2 =" Tension along OQ"#
#Delta POQ, OP=OQ=QP=4m => Delta POQ " equilateral"#
#Delta POQ, " Each angle" = 60^@#
Coparing (1) and (2) we get
Now considering the equilibrium of forces we can say that hrizontal components of
Comparing (3) and (4) we can write
Now from equilibrium point of view the magnitude of Resultant of two tensions
weight of the shaft i.e.
So we can write
When in equilibrium, resultant weigth force passes across the shaft gravity center. The chain and the bar segment between anchored chains, form a equilateral triangle.
The weight passes along the line defined by
we can equate