Question

Question #fe05d

Answer 1

`17.7"ml"`

Explanation:

`Na_2SO_(4(aq))+BaCl_(2(aq))rarrBaSO_(4(s))+2NaCl_((aq))`

A white precipitate of insoluble barium sulfate is formed.

From the equation you can see that the reactants are in a 1:1 molar ratio.

Concentration = no. moles/volume of solution.

`c=n/v`

`:.n=cxxv`

So we can work out the number of moles of barium chloride:

`n_(BaCl_2)=0.218xx26.8/1000=0.00584`

The equation tells us that the number of moles of sodium sulfate must be the same:

`n_(Na_2SO_4)=0.00584`

Since `c=n/v` we can write:

`0.00584/v=0.33`

`:.v=0.00584/0.33=0.0177"L"`

`v=17.7"ml"`