Question #fe05d

1 Answer
Apr 26, 2016

Answer:

#17.7"ml"#

Explanation:

#Na_2SO_(4(aq))+BaCl_(2(aq))rarrBaSO_(4(s))+2NaCl_((aq))#

A white precipitate of insoluble barium sulfate is formed.

From the equation you can see that the reactants are in a 1:1 molar ratio.

Concentration = no. moles/volume of solution.

#c=n/v#

#:.n=cxxv#

So we can work out the number of moles of barium chloride:

#n_(BaCl_2)=0.218xx26.8/1000=0.00584#

The equation tells us that the number of moles of sodium sulfate must be the same:

#n_(Na_2SO_4)=0.00584#

Since #c=n/v# we can write:

#0.00584/v=0.33#

#:.v=0.00584/0.33=0.0177"L"#

#v=17.7"ml"#