Question #d9052

1 Answer
Apr 26, 2016

Answer:

Under #3# #"atmospheres."#

Explanation:

#P=(nRT)/V# #=# #(((0.390*cancel(g))/(4.00*cancel(g)*cancel(mol^-1)))xx0.0821*cancel(L)atmcancel(K^-1)*cancel(mol^-1)xx301cancel(K))/(0.836*cancel(L))#

The only real problem in answering this question is the choice of #R#, the universal gas constant. Chemists would tend to use #R=0.0821*L*atm*K^-1*mol^-1# because it gives an answer in atmospheres, whose magnitude can be readily appreciated.