# In terms of the oxygen atom, how many oxygen atoms are associated with a 49.0*g mass of "sulfuric acid"?

Apr 26, 2016

$2 \times {N}_{A}$, where ${N}_{A} = \text{Avogadro's number, } 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$
We work out (i) the molar quantity of sulfuric acid; and then (ii) mulitply this number by $4 {N}_{A}$.
(i) $\text{Moles of sulfuric acid}$ $=$ $\frac{49.0 \cdot g}{98.08 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.50 \cdot m o l$.
(ii) Because there are 4 atoms of oxygen per formula unit of sulfuric acid, there are $\frac{1}{2} \times 4 \times {N}_{A}$ $=$ $2 {N}_{A}$ $\text{oxygen atoms}$