How much perchloric acid will react with a #20*mL# volume of sodium hydroxide whose concentration is #0.060*mol*L^-1#?

1 Answer
Feb 6, 2017

Answer:

This is something that you will have to address yourself.

Explanation:

We examine the reaction of the strong base, #NaOH#, with #HClO_4#, according to the rxn:

#NaOH(aq) + HClO_4(aq) rarr NaClO_4(aq) + H_2O(l)#

#"Moles of sodium hydroxide"=20.0xx10^-3Lxx0.060*mol*L^-1=1.20xx10^-3*mol.#

Now clearly, we will reach a stoichiometric endpoint when we add #1.20xx10^-3*mol# #"perchloric acid"# solution.

This represents a volume of #(1.20xx10^-3*molxx10^3*mL*L^-1)/(0.040*mol*L^-1)=30*mL#.