How much perchloric acid will react with a $20mL$ volume of sodium hydroxide whose concentration is $0.060mol*L^-1$ ?

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Answer 1 · 2017-02-06T15:04:55

This is something that you will have to address yourself.

We examine the reaction of the strong base, $NaOH$ , with $HClO_4$ , according to the rxn:

$NaOH(aq) + HClO_4(aq) rarr NaClO_4(aq) + H_2O(l)$

$"Moles of sodium hydroxide"=20.0xx10^-3Lxx0.060*mol*L^-1=1.20xx10^-3*mol.$

Now clearly, we will reach a stoichiometric endpoint when we add $1.20xx10^-3*mol$ $"perchloric acid"$ solution.

This represents a volume of $(1.20xx10^-3*molxx10^3*mL*L^-1)/(0.040*mol*L^-1)=30*mL$ .

How much perchloric acid will react with a 20*mL20*mL volume of sodium hydroxide whose concentration is 0.060*mol*L^-10.060*mol*L^-1?