# How much perchloric acid will react with a 20*mL volume of sodium hydroxide whose concentration is 0.060*mol*L^-1?

Feb 6, 2017

This is something that you will have to address yourself.

#### Explanation:

We examine the reaction of the strong base, $N a O H$, with $H C l {O}_{4}$, according to the rxn:

$N a O H \left(a q\right) + H C l {O}_{4} \left(a q\right) \rightarrow N a C l {O}_{4} \left(a q\right) + {H}_{2} O \left(l\right)$

$\text{Moles of sodium hydroxide} = 20.0 \times {10}^{-} 3 L \times 0.060 \cdot m o l \cdot {L}^{-} 1 = 1.20 \times {10}^{-} 3 \cdot m o l .$

Now clearly, we will reach a stoichiometric endpoint when we add $1.20 \times {10}^{-} 3 \cdot m o l$ $\text{perchloric acid}$ solution.

This represents a volume of $\frac{1.20 \times {10}^{-} 3 \cdot m o l \times {10}^{3} \cdot m L \cdot {L}^{-} 1}{0.040 \cdot m o l \cdot {L}^{-} 1} = 30 \cdot m L$.