A 2500*m^3 volume of gas under 200*kPa pressure is compressed to 500*kPa. What is the new volume?

Given constant temperature, we use Boyle's law, $P \propto \frac{1}{V}$
So ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$, and thus,
${V}_{2}$ $=$ $\frac{{P}_{1} {V}_{1}}{P} _ 2$ $=$ $\frac{200 \cdot k P a \times 2500 \cdot {m}^{3}}{500 \cdot k P a}$ $=$ ??*m^3