# Question #5eb7d

The molar mass of $N a C l = 23 + 35.5 = 58.5 \frac{g}{\text{mol}}$
Now 100 mL 2M solution will contain $2 \text{mol"xx58.5g/"mol} \times \frac{100 L}{1000 L} = 11.7 g$
On evaporation 11.7g $N a C l$ will be obtained as residue as it is non volatile solid of high mp.