Question #5eb7d

1 Answer
May 10, 2016

Answer:

11.7g

Explanation:

The molar mass of #NaCl=23+35.5=58.5g/"mol"#
Therefore
1L Or 1000mL 2M Solution contains 2mole solute.
Now 100 mL 2M solution will contain #2"mol"xx58.5g/"mol"xx(100L)/(1000L)=11.7g#
On evaporation 11.7g #NaCl# will be obtained as residue as it is non volatile solid of high mp.