# Question #b85cd

May 11, 2016

$P = 1482 a t m$

#### Explanation:

Assuming that methane is behaving ideally, we can then calculate the pressure using the ideal gas law:

$P V = n R T$.

We will need first to find the number of mole of methane using the mass 885.5 g:

$n = \frac{m}{M M} = \frac{885.5 \cancel{g}}{16.04 \frac{\cancel{g}}{m o l}} = 55.20 m o l C {H}_{4}$

Then, to find the pressure, we can rearrange the expression of the ideal gas law to be:

$P = \frac{n R T}{V} = \frac{55.20 \cancel{m o l} \times 0.08201 \frac{\cancel{L} \cdot a t m}{\cancel{K} \cdot \cancel{m o l}} \times 265.1 \cancel{K}}{0.810 \cancel{L}} = 1482 a t m$