Question #4da3c

Jul 22, 2016

Accelaration/deceleration is according to the formula:
$\Delta v = a \times t \to a = \Delta v / t$,
where $\Delta v =$change in speed, $a =$acceleration, $t =$time

Explanation:

Fill in what we know:
$\Delta v = - 5.8 m / s$ (negative because of slowing down)
$t = 0.059 s$

So $a = \frac{- 5.8}{0.059} \approx - 98.3 m / {s}^{2}$ (the $-$ is for decelaration).

Note:
If you're familiar with the term $g$-force, this amounts to about $10 \times g$, which only trained fighter pilots can stand (for a short time) without losing consciousness.