Question #3f2c0

1 Answer
May 17, 2016

Answer:

#P.MM= d.R.T#

Explanation:

Use the ideal gas equation

#P.V=n.R.T#

#P.V= m/(MM).R.T#

#P.MM= m/V.R.T#

#P.MM= d.R.T#

#P" is the pressure of the gas (" atm")"#
#MM" is the molar mass ("g.mol^-1")"#
#d" is the density of the gas ("g.L^-1")"#k
#R" is the universal gas constant ("0.0821L.\atm.mol^-1.K^-1")" #

Solve for #MM#

#MM= (d.R.T)/P#

#MM= (1.8g.L^-1*0.0821L*\atm*mol^-1*K^-1*300.*K)/((760mmHg*(1.\atm)/(760*mmmHg))#

#MM ~= 44 " "g.mol^-1#