# What is the molarity of an 58.5*g mass of sodium chloride dissolved in enough water to make 1*L of solution?

$\text{Molarity "=" Moles of solute"/"Volume of solution}$
If there are $58 \cdot g$ $N a C l$ solute there are $1$ $m o l$ each solute particles, $N {a}^{+}$, and $C {l}^{-}$ in solution.
And thus $\text{Molarity}$ $=$ $1 \cdot m o l \cdot {L}^{-} 1$ with respect to $N a C l \left(a q\right)$.