What is the molality of a #56*g# mass of common salt dissolved in #18*mL# of water?

2 Answers
May 23, 2016

Answer:

#"Molality"# #=# #"Moles of solute"/"Kilograms of solvent"# #=# #"A somewhat"/" large value"#

Explanation:

#"Molality"# #=# #(1*mol)/(0.018*kg)# #=# #55.6*mol*kg^-1#.

I do not believe that a concentration this strong is physically realistic.

Answer:

5.56 m

Explanation:

Let's assume we have 1 mole of NaCl and 1 mole of water.

Molality is calculated by dividing the moles of solute (NaCl) by the volume in L of the solvent (water)

The trick here is to figure out how much water you have.

The molar mass of water is 18g/mol.
Since the density of water is 1g/mL, 1 mole of water would have a volume of 18mL or 0.18L.

So molality of this would be

Molality = 1 mole NaCl / 0.18L water

5.56 m NaCl

Here is another lesson about calculating molality.

Hope this helps!