# What mass of magnesium chloride is associated with 2.29xx10^23 formula units of magnesium chloride?

##### 1 Answer
Jun 6, 2016

Avogadro's number of $\text{magnesium chloride fomula units}$ have a mass of $95.21 \cdot g$. So you have a mass of approx. $40 \cdot g$.

#### Explanation:

$\left(2.29 \times {10}^{23} \text{ magnesium chloride formula units")/(6.022xx10^23" magnesium chloride formula units per mole}\right)$ $\times$ $95.21 \cdot g \cdot m o {l}^{-} 1$ $=$ ??g