# Question #72cbb

Oct 7, 2016

From the reaction equation it follows that every mole of ${O}_{2}$ will yield two moles of ${H}_{2} O$.

#### Explanation:

Every mole of a gas at STP has a volume of $22.4 L$

So the $44.8 L$ represents 2 moles, that will produce 4 moles of ${H}_{2} O$.

Molar mass of ${H}_{2} O$ is $\approx 2 \times 1 + 1 \times 16 = 18 g$

So we get $4 \text{mol} \times 18 g = 72 g$ of water.