# Question #abb51

May 30, 2016

$M g {\left(N {O}_{3}\right)}_{2}$

#### Explanation:

First you want to look at the charges of both of those atoms. You can easily obtain those from a periodic table, but nitrate, is a polyatomic ion, so if you haven't memorized a bunch of those already, then I recommend you do so.

$M g$ ion has a charge of $+ 2$
$N {O}_{3}^{-}$ (nitrate) has a charge of $- 1$

Question now is how will you make those charges balance?
*Really simple math:

$2 - 1 + x = 0$
$x = - 1$

This step is really unnecasary but if it clarifies the problem, then that's up to you!

Now you need another nitrate atom to balance the charge, thus:
You will have 2 nitrates for every magnesium...

$M g {\left(N {O}_{3}\right)}_{2}$

Brackets are used to indicate $N$ and $O$ count as one atom.