# Question #47267

##### 1 Answer

Here's what I got.

#### Explanation:

The key to this problem is the **density** of the solution.

The density of a substance essentially tells you the mass of **one unit of volume** of that substance. In your case, the density of the solution is said to be *grams per milliliter*, which means that

*one unit of volume*will be

So, the density of the solution tells you that **every**

You can thus use density as a **conversion factor** to help you convert between the *mass* of the solution and the *volume* it occupies.

Now, the problem tries to put you off track a little by telling you that

1000 mLof an extremely viscous solution has a density of#2.5# grams/milliliter...

It **doesn't matter** how much of this solution you have, its density will **always be the same**.

This means that you can ignore the given

A fluid ounce is approximately equal to

#color(purple)(|bar(ul(color(white)(a/a)color(black)("1 fl oz " = " 29.57 mL")color(white)(a/a)|)))#

Use this conversion factor to go from fluid ounces to milliliters

#2 color(red)(cancel(color(black)("fl oz"))) * "29.57 mL"/(1color(red)(cancel(color(black)("fl oz")))) = "59.14 mL"#

Now, if

#59.14 color(red)(cancel(color(black)("mL"))) * overbrace("2.5 g"/(1color(red)(cancel(color(black)("mL")))))^(color(blue)("the density of the solution")) = "147.85 g"#

You *should* round this off to one **sig fig**, the number of sig figs you have for the volume of the solution, i.e.

#"mass of 2 fl oz" = color(green)(|bar(ul(color(white)(a/a)color(black)("150 g")color(white)(a/a)|)))#

Finally, to convert this to *ounces*, use the conversion factor

#color(purple)(|bar(ul(color(white)(a/a)color(black)("1 oz " = " 28.35 g")color(white)(a/a)|)))#

You will have

#150 color(red)(cancel(color(black)("g"))) * "1 oz"/(28.35color(red)(cancel(color(black)("g")))) = color(green)(|bar(ul(color(white)(a/a)color(black)("5.3 oz")color(white)(a/a)|)))#