Question

Question #7dec0

Answer 1

`n = 0.93 "moles"`

Explanation:

Recall `-> Molarity = "no of moles"/"volume of solution"`

`rArr M = n/v`

Where `M = 1.55M or 1.55 molL^-1`

`color(white)(xxxxx) n = ?`

`color(white)(xxxxx) v = 600ML = (600ML)/(1000ML) xx 1L = 0.6L`

`rArr M = n/v`

Making 'n' the subject

`rArr n = M xx v`

`rArr n = 1.55 molL^-1 xx 0.6L`

`rArr n = 1.55 mol cancel(L^-1) xx 0.6cancelL`

`rArr n = (1.55 xx 0.6) mol`

`n = 0.93 "moles"`