Question #7dec0

1 Answer
Aug 25, 2017

Answer:

#n = 0.93 "moles"#

Explanation:

Recall #-> Molarity = "no of moles"/"volume of solution"#

#rArr M = n/v#

Where #M = 1.55M or 1.55 molL^-1#

#color(white)(xxxxx) n = ?#

#color(white)(xxxxx) v = 600ML = (600ML)/(1000ML) xx 1L = 0.6L#

#rArr M = n/v#

Making 'n' the subject

#rArr n = M xx v#

#rArr n = 1.55 molL^-1 xx 0.6L#

#rArr n = 1.55 mol cancel(L^-1) xx 0.6cancelL#

#rArr n = (1.55 xx 0.6) mol #

#n = 0.93 "moles"#