# Question #e8e9c

Jun 4, 2016

$1.07 \times {10}^{\text{-3}} m o l$

#### Explanation:

The temperature and pressure of the gas is not given in the question. It is assumed that it is at STP.

Accoding to the balanced equation 1 mole of $C {O}_{2}$ is produced from 1 mole of $C a C {O}_{3}$

At STP 1mole $C {O}_{2}$ occupies 22400cc.

At STP 24 cc $C {O}_{2}$ will be produced from $\frac{24}{22400} m o l = 1.07 \times {10}^{\text{-3}} m o l C a C {O}_{3}$