Question

Question #ce4e6

Answer 1

The pressure would need to be increased to `16atm`

Explanation:

We can use Boyle's Law `P_1V_1=P_2V_2` to solve for the pressure since the temperature is being held constant.

For this case we are going to use `8L` to represent the original volume and `1L` to represent the `1/8` value of the final volume.

`P_1 = 2atm`
`V_1= 8L`
`P_2=?`
`V_2=1L`

`(2atm)(8L)=(P_2)((1L)`

`((2atm)(8cancelL))/(1cancelL)=((P_2)(cancel(1L)))/(cancel(1L))`

`16atm = P_2`