Question #30ce8

Jun 15, 2017

$14 {w}^{2} - 21 w x - 10 w y - 8 w + 15 x y + 12 x$

Explanation:

We want to distribute to $\left(2 w - 3 x\right) \left(- 4 + 7 w - 5 y\right)$
What we can do is break up the first term : $\textcolor{b l u e}{\left(2 w - 3 x\right)}$

$\textcolor{b l u e}{\left(2 w\right)} \left(- 4 + 7 w - 5 y\right)$

$\textcolor{b l u e}{\left(- 3 x\right)} \left(- 4 + 7 w - 5 y\right)$

Now we can distribute and get our answer:

$\textcolor{b l u e}{\left(2 w\right)} \left(- 4 + 7 w - 5 y\right) = - 8 w + 14 {w}^{2} - 10 w y$

$\textcolor{b l u e}{\left(- 3 x\right)} \left(- 4 + 7 w - 5 y\right) = 12 x - 21 w x + 15 x y$

We now have:

$- 8 w + 14 {w}^{2} - 10 w y + 12 x - 21 w x + 15 x y$

What we can do now is rearrange them:

$14 {w}^{2} - 21 w x - 10 w y - 8 w + 15 x y + 12 x$

I think what made it trick was that there's three variables involved.