# Question #56285

$\frac{1}{16} = {4}^{x}$
$\implies \frac{1}{4} ^ 2 = {4}^{x}$
$\implies {4}^{-} 2 = {4}^{x}$
Since bases on both sides are equal therefore, there exponents must be equal, i.e., $x = - 2.$