# Question #78370

Jun 17, 2016

Probability is $= 0.0612$

#### Explanation:

Given -

Electrical Engineers = 40
Chemical Engineers =20
Mechanical Engineers = 30
Civil Engineers = 10

Total Engineers = 100

In how many ways 4 engineers are selected from
100 engineers ${=}_{100} {\mathbb{C}}_{4} = 3921225$

How may ways one Electrical Engineer is selected from 40 ${=}_{40} {\mathbb{C}}_{1} = 40$

How may ways one Chemical Engineer is selected from 20 ${=}_{20} {\mathbb{C}}_{1} = 20$

How may ways one Mechanical Engineer is selected from 30 ${=}_{30} {\mathbb{C}}_{1} = 30$

How may ways one Civil Engineer is selected from 10 ${=}_{10} {\mathbb{C}}_{1} = 10$

Probability of One Electrical and One Chemical and One Mechanical and One Civil Engineers $= \frac{40 \times 20 \times 30 \times 10}{3921225} = \frac{240000}{3921225} = 0.0612$