# Question #c2f50

##### 1 Answer

Jun 27, 2016

I'm a bit rusty on these, but the density should be the mass of the 4 atoms of rhodium that make up the face centred cubic cell, divided by the volume of the cell.

The correct answer should be (c).

#### Explanation:

First, convert pm into cm:

Next, work out the volume of the FCC cell:

Next work out the average mass of 1 atom of rhodium: 102.9 g/mol divided by

Next, work out the mass of the 4 rhodium atoms in the FCC unit cell:

Finally, work out the density by dividing this last value by the volume of the FCC cell:

Rounding up, closest answer is (c).