# Question #0dc61

Jun 28, 2016

${\text{NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-) -> "NH"_ (3(g)) uarr + "H"_ 2 "O}}_{\left(l\right)}$

#### Explanation:

The ammonium cation, ${\text{NH}}_{4}^{+}$, will react with the hydroxide anion, ${\text{OH}}^{-}$, which is delivered to the solution by the sodium hydroxide, $\text{NaOH}$, to form ammonia, ${\text{NH}}_{3}$, and water.

This is essentially a neutralization reaction that takes place between a weak acid, the ammonium ion, and a strong base, sodium hydroxide.

The balanced chemical equation that describes the reaction looks like this

${\text{NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-) -> "NH"_ (3(g)) uarr + "H"_ 2 "O}}_{\left(l\right)}$

Because ammonia gas is given off, this reaction is used as a confirmatory test for the presence of the ammonium cations.