Question #0dc61

1 Answer
Jun 28, 2016

Answer:

#"NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-) -> "NH"_ (3(g)) uarr + "H"_ 2 "O"_ ((l))#

Explanation:

The ammonium cation, #"NH"_4^(+)#, will react with the hydroxide anion, #"OH"^(-)#, which is delivered to the solution by the sodium hydroxide, #"NaOH"#, to form ammonia, #"NH"_3#, and water.

This is essentially a neutralization reaction that takes place between a weak acid, the ammonium ion, and a strong base, sodium hydroxide.

The balanced chemical equation that describes the reaction looks like this

#"NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-) -> "NH"_ (3(g)) uarr + "H"_ 2 "O"_ ((l))#

Because ammonia gas is given off, this reaction is used as a confirmatory test for the presence of the ammonium cations.