Question

Question #0dc61

Answer 1

`"NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-) -> "NH"_ (3(g)) uarr + "H"_ 2 "O"_ ((l))`

Explanation:

The ammonium cation, `"NH"_4^(+)`, will react with the hydroxide anion, `"OH"^(-)`, which is delivered to the solution by the sodium hydroxide, `"NaOH"`, to form ammonia, `"NH"_3`, and water.

This is essentially a neutralization reaction that takes place between a weak acid, the ammonium ion, and a strong base, sodium hydroxide.

The balanced chemical equation that describes the reaction looks like this

`"NH"_ (4(aq))^(+) + "OH"_ ((aq))^(-) -> "NH"_ (3(g)) uarr + "H"_ 2 "O"_ ((l))`

Because ammonia gas is given off, this reaction is used as a confirmatory test for the presence of the ammonium cations.