Question

Question #d6bd8

Answer 1

B option: `1/7`

Explanation:

When the first bulb is chosen, the probability that it works is

`P"(good)" = 3/7`

Once the first good bulb is chosen, there are only 2 good ones left among the 6 remaining bulbs.

But we want BOTH lbulbs to be good, so

`P"(good, good") =P"(good)"xxP"(good)"`

`= 3/7 xx 2/6 = 1/7`