# Question #fc006

Jul 4, 2016

Test tube 1 contains the silver and so must be ${\text{AgNO}}_{3}$. The silver reacts with sulfide and iodide ions to give the precipitates so you should now see what is in test tubes 2 and 3.

Jul 4, 2016

Mix some of the silver nitrate solution with each of the other tubes to identify the iodide.......

#### Explanation:

Having identified the test tube containing the silver nitrate, add some of this to the contents of each of the other tubes. The one that yields a pale yellow precipitate will be the one containing the potassium iodide.

$K I \left(a q\right)$ + $A g N {O}_{3} \left(a q\right)$ --> $K N {O}_{3} \left(a q\right)$ + $A g I \left(s\right)$

The precipitate is silver iodide.