# Question #01baa

Jul 6, 2016

I think the question should be to prove$\tan x + \cot x = \frac{1}{\sin x \cdot \cos x}$ instead of $\tan x + \cos x = \frac{1}{\sin x \cdot \cos x}$

#### Explanation:

I think the question should be to prove$\tan x + \cot x = \frac{1}{\sin x \cdot \cos x}$

$\tan x + \cot x$ = $\sin \frac{x}{\cos} x + \cos \frac{x}{\sin} x$ =>

=$\frac{\sin x \cdot \sin x}{\sin x \cos x} + \frac{\cos x \cdot \cos x}{\sin x \cdot \cos x}$

= $\left({\sin}^{2} x + {\cos}^{2} x\right)$/ $\left(\sin x \cos x\right)$

= $\frac{1}{\sin x \cos x}$