# Question c89c1

Jul 14, 2016

$\text{5.99 g}$

#### Explanation:

As you can see, the density of aluminium is said to be equal to $\text{2.70 g}$ per $\text{1 mL}$. This tells you that every milliliter of aluminium has a mass of $\text{2.70 g}$.

Since you're dealing with more than $\text{1 mL}$, you can expect the mass of the sample to be bigger than $\text{2.70 g}$. More specifically, the mass of the sample will be

2.22 color(red)(cancel(color(black)("mL"))) * overbrace("2.70 g"/(1color(red)(cancel(color(black)("mL")))))^(color(blue)("the density of Al")) = "5.994 g"

The answer must be rounded off to three sig figs, the number of sig figs you have for the volume of the sample

"mass of sample" = color(green)(|bar(ul(color(white)(a/a)color(black)("5.99 g")color(white)(a/a)|)))#