Question

Question #c89c1

Answer 1

`"5.99 g"`

Explanation:

As you can see, the density of aluminium is said to be equal to `"2.70 g"` per `"1 mL"`. This tells you that every milliliter of aluminium has a mass of `"2.70 g"`.

Since you're dealing with more than `"1 mL"`, you can expect the mass of the sample to be bigger than `"2.70 g"`. More specifically, the mass of the sample will be

`2.22 color(red)(cancel(color(black)("mL"))) * overbrace("2.70 g"/(1color(red)(cancel(color(black)("mL")))))^(color(blue)("the density of Al")) = "5.994 g"`

The answer must be rounded off to three sig figs, the number of sig figs you have for the volume of the sample

`"mass of sample" = color(green)(|bar(ul(color(white)(a/a)color(black)("5.99 g")color(white)(a/a)|)))`