Question #c89c1

1 Answer
Jul 14, 2016

Answer:

#"5.99 g"#

Explanation:

As you can see, the density of aluminium is said to be equal to #"2.70 g"# per #"1 mL"#. This tells you that every milliliter of aluminium has a mass of #"2.70 g"#.

Since you're dealing with more than #"1 mL"#, you can expect the mass of the sample to be bigger than #"2.70 g"#. More specifically, the mass of the sample will be

#2.22 color(red)(cancel(color(black)("mL"))) * overbrace("2.70 g"/(1color(red)(cancel(color(black)("mL")))))^(color(blue)("the density of Al")) = "5.994 g"#

The answer must be rounded off to three sig figs, the number of sig figs you have for the volume of the sample

#"mass of sample" = color(green)(|bar(ul(color(white)(a/a)color(black)("5.99 g")color(white)(a/a)|)))#