Question

Question #a01b0

Answer 1

`"Height"=160m`

Explanation:

Let the height of tower be h m.and the distance of first position from the foot of tower be x m.So the distance of 2nd position from the foot of tbe tower will be `(x-32)` m.

Your correction is cotangent in place of tangent for the 2nd position and 2/5 in place of 2/3 as per book (S.L. Loney)

Hence

For 1st position

`x/h=cot("angle of elevation-1")=3/5.....(1)`

For 2nd position

`(x-32)/h=cot("angle of elevation-2")=2/5..(2)`

subtracting (2) from (1) we can write

`x/h-(x-32)/h=3/5-2/5`

`32/h=1/5`

`:.h=32xx5=160m`