What is the domain and range of the function #x^2+y^2 = 1#?

1 Answer
Nov 14, 2017

Answer:

Both domain and range is #[-1,+1]#

Explanation:

The equation of a circle centred at point #(a,b)# with radius #r# is:
#(x-a)^2 + (y-b)^2 =r^2#

#:. x^2+y^2 = 1# is the equation of a circle centred at the origin with radius 1.

Hence, domain and range are both #[-1, +1]#

We can see this from the graph of #x^2+y^2=1# below.

graph{x^2+y^2=1 [-3.08, 3.08, -1.54, 1.54]}