# What is the mass of a piece of metal that raises the volume of water in a graduated cylinder from #"15.0 cm"^3# to #"70.0 cm"^3# ? the density of iron is #"5.1 g/cm"^3#

##### 1 Answer

#### Answer:

#### Explanation:

The idea here is that the *volume* of the metal will cause the volume of the water to **increase** from its initial value of

In other words, the **difference** between the *final volume* of the water, i.e. the volume of the water + metal, and the *initial volume* of the water will give you the **volume** of the metal

#V_"metal" = "70.0 cm"^3 - "15.0 cm"^3 = "55.0 cm"^3#

Now, the problem tells you the metal has a **density** of **every cubic centimeter** of this metal has a mass of

In your case,

#55.0 color(red)(cancel(color(black)("cm"^3))) * overbrace("5.1 g"/(1color(red)(cancel(color(black)("cm"^3)))))^(color(purple)("given density")) = color(green)(|bar(ul(color(white)(a/a)color(black)("281 g")color(white)(a/a)|)))#

I'll leave the answer rounded to three **sig figs**.