Question

Question #8b2b6

Answer 1

`AB-> "Meter scale"`

`D-> "Position of support where AD"=20 cm`

`C-> "Mid point of the scale i.e. AC"=50cm=>CD=30cm`

`P->"Position of center of mass of the box "`

As the balanced position is achieved, the moments of two forces

`500gwt" at P" and 200gwt " at C"` about D will be equal

Hence `PDxx500=CDxx200=30xx200`

`PD=6000/500=12cm`

So the position `P` of center of mass of the box is such that

`AP = AD-PD=20-12=8 cm`