First of all, you know that the x-intercept is #7# and the y-intercept is #-6#. In addition, by knowing this you can now figure out the equation of this line.

Furthermore, you now have two points you can work with (#7,0# and #0,-6#). To add on, as your next step you will have to find the slope of the line which you can figure out by finding the rise over the run;#(y^2-y^1)/(x^2-x^1)#

Therefore, your #y^2# would be #0# (which comes from the point #7,0#) and your #y^1# would be #-6# (which comes from the point #0, -6#), thus when you subtract #-6# from #0# you get a result of #+6#.

In addition, your #x^2# would be #7# (which comes from the point #7,0#) and your #x^1# would be #0# (which come from the point #0,-6#), thus when you subtract #0# from #7# you get #7#.

So, now that you have the numbers #6# and #7# all you have to do is divide them so that you get the fraction #6/7#. In continuation, from this you can now write the equation of the line which would be #6/7x#(the slope) minus #6# (which is the y-intercept).

*This is a demonstration of how the graph would look like;*

graph{6/7x-6 [-7.65, 12.35, -8.15, 1.85]}

#6/7x-6#