# Question #bbfbd

##### 1 Answer

Domain:

Range:

#### Explanation:

I'm assuming that your function looks like this

#f(x) = 2/(x-1)#

The **domain** of the function includes any value of **defined**. This implies that the domain of the function will **not** include values of

In your case, you have

#x-1 !=0 implies x !=1#

Therefore, you can say that the domain of the function will include any value of **with the exception** of

#f(1) = 2/(1-1) = 2/0 -> # undefined

The domain will thus be

The **range** of the function includes any value of

#f(x) = 0#

That is the case because a fraction can only be equal to zero if its **numerator** is equal to zero.

Here the numerator of the fraction is equal to

graph{2/(x-1) [-10, 10, -5, 5]}

You can use the exact same approach for the function

#f(x) = 2/x - 1#

This time, the value of

#f(0) = 2/0 - 1 -># undefined

The range of the function will include

graph{2/x - 1 [-10, 10, -5, 5]}