Question

Question #bab77

Answer 1

`(3pi)/2 + 2kpi`

Explanation:

Solve this quadratic equation for sin t
`y = sin^2 t - 6sint - 7 = 0`
Since a - b + c = 0, use shortcut. One real root is sin t = -1 and the other is sin t = -c/a = 7 (rejected as > 1)
Trig unit circle -->
sin t = -1 --> arc `t = (3pi)/2`
General answer:
`x = (3pi)/2 + 2kpi`