# Question #bab77

Oct 11, 2016

$\frac{3 \pi}{2} + 2 k \pi$

#### Explanation:

Solve this quadratic equation for sin t
$y = {\sin}^{2} t - 6 \sin t - 7 = 0$
Since a - b + c = 0, use shortcut. One real root is sin t = -1 and the other is sin t = -c/a = 7 (rejected as > 1)
Trig unit circle -->
sin t = -1 --> arc $t = \frac{3 \pi}{2}$
$x = \frac{3 \pi}{2} + 2 k \pi$