# Given the neutral oxide, Mn_3O_4...what are the probable oxidation states of the manganese centres given that the metal expresses ONLY two oxidation states in this species?

##### 1 Answer
Jan 5, 2018

The sum of the oxidation numbers equals the charge on the ion...

#### Explanation:

Of course, here, the parent species is NEUTRAL, and therefore the sum of the oxidation numbers EQUALS ZERO.

The oxidation number of oxygen, as oxide, is typically $- I I$...and so $3 \times M {n}_{\text{oxidation number}} - 8 = 0$...$M {n}_{\text{average oxidation number}} = + \frac{8}{3}$...and so we gots $2 \times M {n}^{+ I I I} + M {n}^{+ I I}$...

The solid state structure does correspond to a formulation of $M n O \cdot M {n}_{2} {O}_{3}$...the which does reflect the oxidation states we assigned. Capisce?