# Simplify the equation (12^x+1)/(6^(2x)+3^x)?

Aug 7, 2016

$\frac{{12}^{x} + 1}{{6}^{2 x} + {3}^{x}} = \frac{1}{3} ^ x$

#### Explanation:

This is not an equation but a function of $x$ and you can simplify it as follows:

$\frac{{12}^{x} + 1}{{6}^{2 x} + {3}^{x}}$

= $\frac{{12}^{x} + 1}{{\left({6}^{2}\right)}^{x} + {3}^{x}}$

= $\frac{{12}^{x} + 1}{{\left(36\right)}^{x} + {3}^{x}}$

= $\frac{{12}^{x} + 1}{{\left(3 \times 12\right)}^{x} + {3}^{x}}$

= (12^x+1)/((3^x xx12^x+3^x)

= (12^x+1)/(3^x(12^x+1)

= $\frac{1}{3} ^ x$