# 18.9*g of ammonium nitrate is dissolved in a 855*mL volume of water. What is the concentration of the salt?

$\text{Molarity"="Moles of solute"/"Volume of solution}$
And thus $\text{molarity}$ $=$ $\frac{\frac{18.9 \cdot g}{80.04 \cdot g \cdot m o {l}^{-} 1}}{0.855 \cdot L}$ $=$ ??*mol*L^-1.