Question

How do you simplify `cot x xx sin x`?

Answer 1

`(cos x)/(sin x) xx sinx`

=`cosx`

Explanation:

All of the 6 trig ratios can be expressed in terms of `sin theta` and / or `cos theta`

`tan theta = (sin theta)/(cos theta) " "(o/h)/(a/h) = (o xxh)/(axxh) = o/a`

`cot theta = 1/(tan theta) = (cos theta)/(sin theta)`

`sec theta = 1/(cos theta)`

`cosec theta =1/(sin theta)`

`cotx xxsinx`

=`(cos x)/cancel(sin x) xxcancel sinx`

=`cosx`