Question #40068

1 Answer
Aug 18, 2016

Bouyant force will decrease as it makes the volume of the object

Explanation:

As Archimedes' principle explains:

The apparent weight of an object, #W_"apparent"#, in a fluid equals to its weight, #W#, minus the weight of the fluid which occupes its volume, #B#

#W_"apparent" = W - B#

where #B# is buoyant force.

If you put a body on a fluid, it will occupe some volume of fluid. If this fluid has a density #rho#, and the volume of the object is #V#, the mass of fluid which will be occupied is:

#m_"fluid" = rho V#

And the weight of this mass is right the buoyant force:

#B = m_"fluid" cdot g = rho V g#

As you see, buoyant force does not depend on the mass of the submerged body, but its volume. If you decrease its size, #B# will reduce.