# How do you solve #2x^2 -: 3x = 14# ?

##### 1 Answer

Aug 20, 2016

See explanation...

#### Explanation:

I think the question should have had subtraction rather than division, but I will answer both possibilities:

**How to solve #bb((2x^2)/(3x)=14)#**

Multiply both sides by

#2x^2 = 42x#

Divide both sides by

#x = 21#

**How to solve #bb(2x^2-3x=14)#**

Subtract

#2x^2-3x-14 = 0#

Use an AC method to factorise:

Look for a pair of factors of

The pair

Use this to split the middle term then factor by grouping:

#0 = 2x^2-3x-14#

#=2x^2-7x+4x-14#

#=(2x^2-7x)+(4x-14)#

#=x(2x-7)+2(2x-7)#

#=(x+2)(2x-7)#

Hence